Linear Algebra Examples

- 3 x + [\begin{array}{c} 7 & 0 & - 1 \\ 2 & - 3 & 4 \end{array}] = [\begin{array}{c} 10 & 0 & 8 \\ - 19 & - 18 & 10 \end{array}]

$- 3 x + [\begin{array}{c} 7 & 0 & - 1 \\ 2 & - 3 & 4 \end{array}] = [\begin{array}{c} 10 & 0 & 8 \\ - 19 & - 18 & 10 \end{array}]$

Step 1

Move all terms not containing a variable to the right side.

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Step 1.1

Subtract

[\begin{array}{c} 7 & 0 & - 1 \\ 2 & - 3 & 4 \end{array}]

$[\begin{array}{c} 7 & 0 & - 1 \\ 2 & - 3 & 4 \end{array}]$ from both sides of the equation.

- 3 x = [\begin{array}{c} 10 & 0 & 8 \\ - 19 & - 18 & 10 \end{array}] - [\begin{array}{c} 7 & 0 & - 1 \\ 2 & - 3 & 4 \end{array}]

$- 3 x = [\begin{array}{c} 10 & 0 & 8 \\ - 19 & - 18 & 10 \end{array}] - [\begin{array}{c} 7 & 0 & - 1 \\ 2 & - 3 & 4 \end{array}]$

- 3 x = [\begin{array}{c} 10 & 0 & 8 \\ - 19 & - 18 & 10 \end{array}] - [\begin{array}{c} 7 & 0 & - 1 \\ 2 & - 3 & 4 \end{array}]

$- 3 x = [\begin{array}{c} 10 & 0 & 8 \\ - 19 & - 18 & 10 \end{array}] - [\begin{array}{c} 7 & 0 & - 1 \\ 2 & - 3 & 4 \end{array}]$

Step 2

Simplify the right side.

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Step 2.1

Subtract the corresponding elements.

- 3 x = [\begin{array}{c} 10 - 7 & 0 - 0 & 8 + 1 \\ - 19 - 2 & - 18 + 3 & 10 - 4 \end{array}]

$- 3 x = [\begin{array}{c} 10 - 7 & 0 - 0 & 8 + 1 \\ - 19 - 2 & - 18 + 3 & 10 - 4 \end{array}]$

Step 2.2

Simplify each element.

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Step 2.2.1

Subtract

7

$7$ from

10

$10$ .

- 3 x = [\begin{array}{c} 3 & 0 - 0 & 8 + 1 \\ - 19 - 2 & - 18 + 3 & 10 - 4 \end{array}]

$- 3 x = [\begin{array}{c} 3 & 0 - 0 & 8 + 1 \\ - 19 - 2 & - 18 + 3 & 10 - 4 \end{array}]$

Step 2.2.2

Subtract

0

$0$ from

0

$0$ .

- 3 x = [\begin{array}{c} 3 & 0 & 8 + 1 \\ - 19 - 2 & - 18 + 3 & 10 - 4 \end{array}]

$- 3 x = [\begin{array}{c} 3 & 0 & 8 + 1 \\ - 19 - 2 & - 18 + 3 & 10 - 4 \end{array}]$

Step 2.2.3

Add

8

$8$ and

1

$1$ .

- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 19 - 2 & - 18 + 3 & 10 - 4 \end{array}]

$- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 19 - 2 & - 18 + 3 & 10 - 4 \end{array}]$

Step 2.2.4

Subtract

2

$2$ from

- 19

$- 19$ .

- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 18 + 3 & 10 - 4 \end{array}]

$- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 18 + 3 & 10 - 4 \end{array}]$

Step 2.2.5

Add

- 18

$- 18$ and

3

$3$ .

- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 10 - 4 \end{array}]

$- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 10 - 4 \end{array}]$

Step 2.2.6

Subtract

4

$4$ from

10

$10$ .

- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$- 3 x = [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

Step 3

Multiply both sides by

- \frac{1}{3}

$- \frac{1}{3}$ .

- \frac{1}{3} (- 3 x) = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$- \frac{1}{3} (- 3 x) = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

Step 4

Simplify.

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Step 4.1

Cancel the common factor of

3

$3$ .

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Step 4.1.1

Move the leading negative in

- \frac{1}{3}

$- \frac{1}{3}$ into the numerator.

\frac{- 1}{3} (- 3 x) = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$\frac{- 1}{3} (- 3 x) = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

Step 4.1.2

Factor

3

$3$ out of

- 3 x

$- 3 x$ .

\frac{- 1}{3} (3 (- x)) = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$\frac{- 1}{3} (3 (- x)) = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

Step 4.1.3

Cancel the common factor.

\frac{- 1}{3} (3 (- x)) = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$\frac{- 1}{3} (3 (- x)) = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

Step 4.1.4

Rewrite the expression.

- - x = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$- - x = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

- - x = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$- - x = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

Step 4.2

Multiply

- 1

$- 1$ by

- 1

$- 1$ .

1 x = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$1 x = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

Step 4.3

Multiply

x

$x$ by

1

$1$ .

x = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]

$x = - \frac{1}{3} [\begin{array}{c} 3 & 0 & 9 \\ - 21 & - 15 & 6 \end{array}]$

Step 4.4

Multiply

- \frac{1}{3}

$- \frac{1}{3}$ by each element of the matrix.

x = [\begin{array}{c} - \frac{1}{3} \cdot 3 & - \frac{1}{3} \cdot 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - \frac{1}{3} \cdot 3 & - \frac{1}{3} \cdot 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5

Simplify each element in the matrix.

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Step 4.5.1

Cancel the common factor of

3

$3$ .

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Step 4.5.1.1

Move the leading negative in

- \frac{1}{3}

$- \frac{1}{3}$ into the numerator.

x = [\begin{array}{c} \frac{- 1}{3} \cdot 3 & - \frac{1}{3} \cdot 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} \frac{- 1}{3} \cdot 3 & - \frac{1}{3} \cdot 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.1.2

Cancel the common factor.

x = [\begin{array}{c} \frac{- 1}{3} \cdot 3 & - \frac{1}{3} \cdot 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} \frac{- 1}{3} \cdot 3 & - \frac{1}{3} \cdot 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.1.3

Rewrite the expression.

x = [\begin{array}{c} - 1 & - \frac{1}{3} \cdot 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & - \frac{1}{3} \cdot 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

x = [\begin{array}{c} - 1 & - \frac{1}{3} \cdot 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & - \frac{1}{3} \cdot 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.2

Multiply

- \frac{1}{3} \cdot 0

$- \frac{1}{3} \cdot 0$ .

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Step 4.5.2.1

Multiply

0

$0$ by

- 1

$- 1$ .

x = [\begin{array}{c} - 1 & 0 (\frac{1}{3}) & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 (\frac{1}{3}) & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.2.2

Multiply

0

$0$ by

\frac{1}{3}

$\frac{1}{3}$ .

x = [\begin{array}{c} - 1 & 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

x = [\begin{array}{c} - 1 & 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - \frac{1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.3

Cancel the common factor of

3

$3$ .

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Step 4.5.3.1

Move the leading negative in

- \frac{1}{3}

$- \frac{1}{3}$ into the numerator.

x = [\begin{array}{c} - 1 & 0 & \frac{- 1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & \frac{- 1}{3} \cdot 9 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.3.2

Factor

3

$3$ out of

9

$9$ .

x = [\begin{array}{c} - 1 & 0 & \frac{- 1}{3} \cdot (3 (3)) \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & \frac{- 1}{3} \cdot (3 (3)) \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.3.3

Cancel the common factor.

x = [\begin{array}{c} - 1 & 0 & \frac{- 1}{3} \cdot (3 \cdot 3) \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & \frac{- 1}{3} \cdot (3 \cdot 3) \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.3.4

Rewrite the expression.

x = [\begin{array}{c} - 1 & 0 & - 1 \cdot 3 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 1 \cdot 3 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

x = [\begin{array}{c} - 1 & 0 & - 1 \cdot 3 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 1 \cdot 3 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.4

Multiply

- 1

$- 1$ by

3

$3$ .

x = [\begin{array}{c} - 1 & 0 & - 3 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ - \frac{1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.5

Cancel the common factor of

3

$3$ .

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Step 4.5.5.1

Move the leading negative in

- \frac{1}{3}

$- \frac{1}{3}$ into the numerator.

x = [\begin{array}{c} - 1 & 0 & - 3 \\ \frac{- 1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ \frac{- 1}{3} \cdot - 21 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.5.2

Factor

3

$3$ out of

- 21

$- 21$ .

x = [\begin{array}{c} - 1 & 0 & - 3 \\ \frac{- 1}{3} \cdot (3 (- 7)) & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ \frac{- 1}{3} \cdot (3 (- 7)) & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.5.3

Cancel the common factor.

x = [\begin{array}{c} - 1 & 0 & - 3 \\ \frac{- 1}{3} \cdot (3 \cdot - 7) & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ \frac{- 1}{3} \cdot (3 \cdot - 7) & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.5.4

Rewrite the expression.

x = [\begin{array}{c} - 1 & 0 & - 3 \\ - 1 \cdot - 7 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ - 1 \cdot - 7 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

x = [\begin{array}{c} - 1 & 0 & - 3 \\ - 1 \cdot - 7 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ - 1 \cdot - 7 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.6

Multiply

- 1

$- 1$ by

- 7

$- 7$ .

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & - \frac{1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.7

Cancel the common factor of

3

$3$ .

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Step 4.5.7.1

Move the leading negative in

- \frac{1}{3}

$- \frac{1}{3}$ into the numerator.

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & \frac{- 1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & \frac{- 1}{3} \cdot - 15 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.7.2

Factor

3

$3$ out of

- 15

$- 15$ .

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & \frac{- 1}{3} \cdot (3 (- 5)) & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & \frac{- 1}{3} \cdot (3 (- 5)) & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.7.3

Cancel the common factor.

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & \frac{- 1}{3} \cdot (3 \cdot - 5) & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & \frac{- 1}{3} \cdot (3 \cdot - 5) & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.7.4

Rewrite the expression.

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & - 1 \cdot - 5 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & - 1 \cdot - 5 & - \frac{1}{3} \cdot 6 \end{array}]$

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & - 1 \cdot - 5 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & - 1 \cdot - 5 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.8

Multiply

- 1

$- 1$ by

- 5

$- 5$ .

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - \frac{1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - \frac{1}{3} \cdot 6 \end{array}]$

Step 4.5.9

Cancel the common factor of

3

$3$ .

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Step 4.5.9.1

Move the leading negative in

- \frac{1}{3}

$- \frac{1}{3}$ into the numerator.

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & \frac{- 1}{3} \cdot 6 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & \frac{- 1}{3} \cdot 6 \end{array}]$

Step 4.5.9.2

Factor

3

$3$ out of

6

$6$ .

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & \frac{- 1}{3} \cdot (3 (2)) \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & \frac{- 1}{3} \cdot (3 (2)) \end{array}]$

Step 4.5.9.3

Cancel the common factor.

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & \frac{- 1}{3} \cdot (3 \cdot 2) \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & \frac{- 1}{3} \cdot (3 \cdot 2) \end{array}]$

Step 4.5.9.4

Rewrite the expression.

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - 1 \cdot 2 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - 1 \cdot 2 \end{array}]$

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - 1 \cdot 2 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - 1 \cdot 2 \end{array}]$

Step 4.5.10

Multiply

- 1

$- 1$ by

2

$2$ .

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - 2 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - 2 \end{array}]$

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - 2 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - 2 \end{array}]$

x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - 2 \end{array}]

$x = [\begin{array}{c} - 1 & 0 & - 3 \\ 7 & 5 & - 2 \end{array}]$